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Atoms Get Smaller as You Add Protons Across a Row of the Table

Define atomic size, ionisation potential, electron affinity and electronegativity, explain why each changes across a period and down a group in terms of nuclear charge and shells, and put any set of elements in order of size, reactivity or electronegativity.

Why would an atom with more electrons ever be smaller?

Sodium has eleven electrons and chlorine has seventeen, in the same number of shells. You might expect chlorine, with six more electrons, to be the bigger atom. It is noticeably smaller.

The extra electrons are not the whole story, because each step from sodium to chlorine adds a proton to the nucleus as well. **The nuclear charge rises from to , while the new electrons go into the same third shell, which is no further away than before. So the growing positive charge pulls the whole electron cloud inward, and the atom shrinks.

That single picture — more pull, same distance — explains every trend across a period in this chapter.

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Atomic size decreases, because the outer electrons are pulled in harder
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Ionisation potential increases, because a tightly held electron is harder to remove
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Electron affinity and electronegativity increase, because a strong nucleus attracts an extra or shared electron more
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Metallic character decreases, because losing electrons becomes harder

Down a group the picture changes. Each step down adds a whole new shell, so the outer electrons sit further from the nucleus and are screened by more inner electrons. The extra nuclear charge is more than cancelled by the extra distance and shielding, so every one of those trends runs the other way.

So the chapter rests on two competing effects, and every question is a matter of deciding which one wins:

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Nuclear charge, which pulls outer electrons in and dominates across a period
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Number of shells, which pushes them out and shields them, and dominates down a group

Once that is clear, putting elements in order becomes reasoning rather than memory.** Given any two elements, find where they sit, decide which effect separates them, and the order follows.

This page covers the second part of the ICSE Class 10 Chemistry chapter on periodic properties: the definitions of the periodic properties, their variation across a period and down a group, and arranging elements by these properties.

What do atomic size, ionisation potential, electron affinity and electronegativity mean?

Each measures a different aspect of how strongly an atom holds, loses or attracts electrons.

Atomic size, or atomic radius. The distance between the centre of the nucleus and the outermost shell of an isolated atom. It measures how far out the outer electrons are.

Metallic character. The tendency of an atom to lose electrons and form a positive ion. Elements with this tendency are called electropositive.

Non-metallic character. The tendency of an atom to gain electrons and form a negative ion. Elements with this tendency are called electronegative.

Ionisation potential, or ionisation energy. The amount of energy required to remove the most loosely held electron from an isolated gaseous atom, converting it into a positive ion.



Energy is supplied, so a large ionisation potential means the electron is held tightly. Metals have low ionisation potentials, which is why they lose electrons easily.

Electron affinity. The amount of energy released when an electron is added to an isolated neutral gaseous atom, converting it into a negative ion.



Energy is given out, so a large electron affinity means the atom readily accepts an electron. Halogens have the highest electron affinities in their periods.

Electronegativity. The tendency of an atom in a molecule to attract the shared pair of electrons of a covalent bond towards itself.

The difference between the last two is worth stating carefully, because they sound alike:

- Electron affinity belongs to an isolated atom gaining a whole electron, and it is an energy
- Electronegativity belongs to an atom already bonded in a molecule, pulling on a shared pair, and it is a tendency compared on a relative scale

Fluorine is the most electronegative element of all, and it sits at the top right of the table, excluding the noble gases.

Worked example — reading the definitions. Which process needs energy and which releases it: sodium forming , or chlorine forming ?

- **Forming removes an electron, which is ionisation, so energy must be supplied
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Forming adds an electron, which is electron affinity, so energy is released

And that is exactly why sodium and chlorine combine so readily — the energy released by chlorine and by the attraction of the ions more than pays for the energy sodium needs.

Size of ions, a useful extension. A positive ion is smaller than its parent atom, because it has lost electrons — often a whole shell — while the nuclear charge is unchanged. A negative ion is larger** than its parent atom, because the added electron is repelled by the others and the same nuclear charge is spread over more electrons.



One boundary case about the noble gases. They have complete shells, so they neither lose nor gain electrons readily. Their ionisation potentials are the highest in each period, their electron affinities practically zero, and electronegativity is not normally assigned to them because they do not ordinarily form bonds.

How do the periodic properties change across a period?

Across a period, from left to right, atomic size decreases while ionisation potential, electron affinity and electronegativity increase, and metallic character gives way to non-metallic character.

The cause, in one line. Across a period the nuclear charge increases by one at each step, but the electrons are added to the same outer shell. The shell is no further away, so the stronger nucleus pulls it closer.

Atomic size decreases.



- **Sodium, with nuclear charge , holds its third-shell electron loosely and is the largest
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Chlorine, with nuclear charge , pulls its third shell in hardest and is the smallest

Ionisation potential increases. A smaller atom with a stronger nucleus holds its outer electrons more tightly, so more energy is needed to remove one. Sodium has the lowest ionisation potential in Period 3 and argon the highest.

Electron affinity increases. A stronger, closer nucleus attracts an incoming electron more, so more energy is released when it is added. The halogen at the end of each period has the highest electron affinity, since one electron completes its octet.

Electronegativity increases. The same stronger pull acts on a shared pair of electrons. In Period 2 it rises from lithium to fluorine, and fluorine is the most electronegative element.

Metallic character decreases and non-metallic character increases.

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Sodium, magnesium and aluminium are metals, losing electrons readily
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Silicon is a metalloid
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Phosphorus, sulphur and chlorine are non-metals, gaining electrons readily

And the nature of the oxides changes in step: sodium and magnesium oxides are basic, aluminium oxide is amphoteric, and the oxides of silicon, phosphorus, sulphur and chlorine are acidic.

Worked example 1. Arrange lithium, fluorine, carbon and oxygen in order of increasing atomic size.

All four are in Period 2**, so the one furthest right is smallest:



Worked example 2. Which has the higher ionisation potential, magnesium or sulphur? Give a reason.

Sulphur, because both are in Period 3 and sulphur, further right, has the greater nuclear charge acting on the same shell — so its outer electrons are held more tightly.

Worked example 3. Arrange sodium, aluminium and magnesium in order of decreasing metallic character.



Sodium loses its single electron most easily, while aluminium must lose three against a stronger nuclear pull.

One honest qualification about ionisation potential. The increase across a period is the general trend, and it holds for every comparison you are asked at this level between elements that are well apart. A few neighbouring pairs show small irregularities — for example between magnesium and aluminium — which are explained in Class 11 once orbitals are introduced. For a Class 10 answer, state the general trend and its reason.

One boundary case about size. The noble gas at the end of each period is not included in size comparisons across the period. Its radius is measured in a different way, because it does not form bonds, and it appears larger than the halogen before it — so a size order across Period 3 stops at chlorine.

Why do these properties change the other way down a group, and why does metallic character rise?

Down a group a new shell is added at each step, so the outer electrons are further from the nucleus and more shielded — and that outweighs the increase in nuclear charge.

The two effects of adding a shell:

- Greater distance — the outer electrons are simply further away, and the attraction falls with distance
- Greater shielding — the extra inner shells screen the outer electrons from the nucleus, so they feel much less of its charge

The nuclear charge does increase down a group, and considerably, but the added shell more than cancels it.

Atomic size increases.



Each step adds a shell, so each atom is larger than the one above it.

Ionisation potential decreases. The outer electron is further away and better shielded, so it is removed more easily.



Electron affinity decreases. A larger atom attracts an incoming electron less strongly. In general it falls down a group, as in the halogens from chlorine downwards.

Electronegativity decreases.



Metallic character increases, and this is the trend the chapter asks you to explain specifically.

- Metallic character is the tendency to lose electrons
- Down a group the outer electrons are further out and more shielded, so they are lost more easily
- So the elements become more metallic

The clearest illustration is group 14: carbon at the top is a non-metal, silicon and germanium are metalloids, and tin and lead at the bottom are metals. One group, running from non-metal to metal, entirely because the outer electrons become easier to lose as the atoms grow.

Reactivity, which follows from the same reasoning:

- For metals, reactivity increases down a group — potassium is more reactive than sodium, which is more reactive than lithium — because losing electrons gets easier
- For non-metals, reactivity decreases down a group — fluorine is more reactive than chlorine, chlorine than bromine — because gaining electrons gets harder

Worked example 1. Explain why potassium is more reactive than sodium.

**Potassium, , has its outer electron in the fourth shell; sodium, , in the third. Potassium's electron is further from the nucleus and shielded by one more inner shell, so its ionisation potential is lower and it loses that electron more readily. Losing electrons is what a metal does when it reacts, so potassium reacts more vigorously.

Worked example 2. Explain why fluorine is more reactive than chlorine.

Fluorine, , is much smaller than chlorine, , so its nucleus attracts an incoming electron more strongly. Gaining electrons is what a non-metal does when it reacts, so fluorine reacts more vigorously.

A boundary case that is worth knowing rather than being surprised by. Although electron affinity generally falls down a group, chlorine releases slightly more energy than fluorine on gaining an electron. Fluorine's second shell is so small and crowded that the incoming electron is repelled by the electrons already there.** Fluorine nevertheless remains the more reactive element and the more electronegative one — so this exception affects the electron affinity order only, and it is the kind of detail that appears again in Class 11.

How do you arrange elements in order of size, ionisation potential or reactivity?

Locate each element, decide whether the comparison is along a period or down a group, apply the corresponding trend, and check the result against the reason.

The two summary rules to apply:

- Across a period, left to right: size decreases; ionisation potential, electron affinity and electronegativity increase; metallic character decreases
- Down a group, top to bottom: size increases; ionisation potential, electron affinity and electronegativity decrease; metallic character increases

So the extreme corners are predictable. The largest, most metallic, lowest-ionisation elements lie at the bottom left of the table, and the smallest, most electronegative, highest-ionisation elements lie at the top right, excluding the noble gases.

Worked example 1 — size along a period. Arrange chlorine, sodium, sulphur and magnesium in increasing order of atomic size.

All in Period 3, so size falls from left to right:



Worked example 2 — ionisation potential down a group. Arrange potassium, lithium and sodium in increasing order of ionisation potential.

All in group 1, so ionisation potential falls down the group:



Worked example 3 — electronegativity down a group. Arrange iodine, fluorine, bromine and chlorine in decreasing order of electronegativity.



Worked example 4 — reactivity of metals. Which is the most reactive metal among lithium, sodium and potassium, and why?

Potassium, the lowest in the group, has the largest atom and the lowest ionisation potential, so it loses its electron most easily.

Worked example 5 — reactivity of non-metals. Which is the most reactive non-metal among fluorine, chlorine and bromine?

Fluorine, the highest in the group, is the smallest atom and attracts an electron most strongly.

Worked example 6 — elements in different periods and groups. Which is larger, oxygen or sulphur? Which has the higher ionisation potential, sodium or chlorine?

- Sulphur is larger than oxygen — both in group 16, and sulphur has one more shell
- Chlorine has the higher ionisation potential — both in Period 3, and chlorine is further right with a greater nuclear charge

Worked example 7 — a mixed comparison that needs care. Arrange sodium, potassium and magnesium in increasing order of ionisation potential.

Split the comparison into its two directions. Potassium lies below sodium in group 1, so potassium is lower than sodium. Magnesium lies to the right of sodium in Period 3, so magnesium is higher than sodium. Putting the two together:



Worked example 8 — identifying elements from properties. Of the elements lithium, carbon, fluorine and neon in Period 2, which has the largest atomic size, which the highest electronegativity, and which the highest ionisation potential?

- Largest atomic size: lithium, at the left of the period
- Highest electronegativity: fluorine
- Highest ionisation potential: neon, whose complete shell holds its electrons most tightly of all

Notice the last one. Neon is excluded from the electronegativity and size comparisons but not from the ionisation potential comparison, where its complete shell gives it the highest value in the period. Reading which property is asked decides whether the noble gas belongs in the answer.

The check that catches most ordering errors. After writing an order, ask whether the reason agrees. If you have put the more metallic element as having the higher ionisation potential, one of the two is wrong, because metallic character and ionisation potential always run opposite to each other.
Exam tip

What does a full-mark periodic trends answer include?

Give the trend, then give the reason in terms of nuclear charge and shells. A trend without its reason usually earns half the marks.

- Across a period, name the cause: nuclear charge increases while electrons enter the same shell
- Down a group, name the cause: a new shell is added, increasing distance and shielding, which outweighs the increased nuclear charge
- Define ionisation potential as energy supplied and electron affinity as energy released, and include "isolated gaseous atom" in both
- Distinguish electron affinity from electronegativity — an isolated atom gaining an electron against a bonded atom attracting a shared pair
- Exclude noble gases from size and electronegativity comparisons, but include them for ionisation potential
- Say metallic character is the tendency to lose electrons before explaining why it rises down a group
- Give opposite reactivity trends for metals and non-metals down a group, with the reason for each
- Write orders with inequality signs in the direction the question asks — increasing or decreasing
- Split mixed comparisons into a period step and a group step
- Remember that a cation is smaller and an anion larger than its parent atom

The misconception to name. More electrons do not make a bigger atom across a period. Chlorine has more electrons than sodium and is smaller, because the extra protons pull the same shell closer. Size depends on how many shells there are and how strongly they are pulled, not on the total count of electrons, and an answer based on electron count alone reverses the trend.

A second trap. Stating that ionisation potential increases down a group because the nuclear charge increases. The nuclear charge does increase, but the added shell more than cancels it, so ionisation potential decreases. Giving only the nuclear-charge argument for a group comparison is the commonest reasoning error in this chapter.
Did you know

Why is caesium soft enough to melt in your hand while fluorine attacks glass?

Caesium, near the bottom left of the table, is a metal so soft and with so low a melting point that it melts just above room temperature. Fluorine, at the top right, is a pale gas so reactive that it attacks glass and sets many substances alight. The two elements are about as far apart in the table as it is possible to be, and their behaviour reflects that distance exactly.

Caesium's single outer electron sits in the sixth shell, very far from the nucleus and shielded by five complete shells beneath it. It is held so weakly that caesium gives it up at the slightest opportunity — reacting explosively with water and even losing electrons when light falls on it, which is why it has been used in light-sensitive devices.

Fluorine is the opposite in every respect. Its seven outer electrons are in only the second shell, very close to a nucleus with almost no shielding. The atom is tiny, the pull is intense, and it grabs an electron from almost anything it meets. It is the most electronegative element and one of the most reactive.

So the two corners of the table are the two extremes of one idea.

- Bottom left: largest atoms, lowest ionisation potential, most metallic, most eager to lose electrons
- Top right: smallest atoms, highest electronegativity, most non-metallic, most eager to gain electrons

And bring them together and the result is dramatic: an element that cannot wait to lose an electron meeting one that cannot wait to gain one. That pairing, of a low-ionisation metal with a high-affinity non-metal, is exactly the condition for an electrovalent bond — which is why the next chapter, on chemical bonding, begins where this one ends.

The same reasoning explains a quieter everyday fact. Common salt, sodium chloride, is so stable that it is spread on food and dissolved in the sea. Sodium and chlorine separately are a violently reactive metal and a poisonous gas, but once sodium has lost its electron and chlorine has gained it, both have complete octets and neither has any further tendency to react. The trends in this chapter explain both the danger of the elements and the safety of the compound, and that is a good illustration of why position in the table is so informative.
Exam relevance

How are periodic trends tested in JEE and NEET?

This is foundation work for Class 11 Classification of Elements and Periodicity in Properties, one of the most reliably examined chapters in both JEE Main and NEET Chemistry.

Where the four definitions lead. Class 11 renames two of them — ionisation enthalpy and electron gain enthalpy — and gives them signs, so that the energy released on gaining an electron is written as negative. The physical meaning is exactly what you learn here, and the sign convention is a frequent source of errors for candidates who have not first understood which process absorbs and which releases energy.

Where the trends lead. Every trend on this page is examined directly, and the questions go further by asking for the exceptions. The irregularity between magnesium and aluminium, the similar one between nitrogen and oxygen, and chlorine's electron affinity exceeding fluorine's are all standard objective questions, explained through orbital configurations and electron repulsion. The boundary cases mentioned here are the starting points of those explanations.

Where electronegativity leads. It becomes central to Class 11 Chemical Bonding, where the difference in electronegativity decides whether a bond is ionic or covalent and how polar it is, and to organic chemistry, where it explains the direction of inductive effects. Knowing that fluorine is the most electronegative element and that the value falls down a group is assumed throughout.

Where ionic size leads. Class 11 compares the sizes of isoelectronic species — ions with the same number of electrons, such as the oxide, fluoride, sodium and magnesium ions — and orders them by nuclear charge. Your rule that a cation is smaller and an anion larger than its parent atom is the first step, and ordering isoelectronic ions is a recurring JEE Main and NEET question.

Where metallic character leads. The acidic, basic and amphoteric nature of oxides across a period and down a group is examined repeatedly, and the group 14 progression from non-metal to metal reappears in the p-block chapter.

Question types to expect. At this level: definitions, trend explanations, and ordering sets of elements. In competitive papers: ordering including exceptions, isoelectronic ion sizes, sign conventions for electron gain enthalpy, and assertion-reason items linking size to ionisation enthalpy.

The single trap that costs marks. Giving the nuclear-charge argument for a group trend. Down a group the added shell wins, so ionisation enthalpy falls even though the nuclear charge rises — and an answer that follows nuclear charge alone gets the direction wrong.

A second trap. Assuming electron affinity follows electronegativity exactly. Fluorine is more electronegative than chlorine, but chlorine has the larger electron affinity — a genuine exception that both exams test precisely because the two properties are so easily confused.

Board versus competitive emphasis. The ICSE paper marks the definition, the direction of the trend and the reason in terms of nuclear charge and shells; a competitive paper marks an ordering, frequently one that includes an exception. The transferable habit is naming which effect dominates — nuclear charge or shells — before writing any order, because the exceptions are only understandable once the main rule is secure.
Key takeaways

What must you be able to do from this part?

Two competing effects, four definitions and one method for ordering.

- Atomic size is the distance from the nucleus to the outermost shell
- Metallic character is the tendency to lose electrons; non-metallic character the tendency to gain them
- Ionisation potential is the energy supplied to remove the most loosely held electron from an isolated gaseous atom:
- Electron affinity is the energy released when an electron is added to an isolated gaseous atom:
- Electronegativity is the tendency of a bonded atom to attract a shared pair; fluorine is the most electronegative element
- A cation is smaller and an anion larger than its parent atom
- Across a period nuclear charge rises while electrons enter the same shell, so size decreases and ionisation potential, electron affinity and electronegativity increase, while metallic character decreases
- Period 3 size:
- Down a group a new shell adds distance and shielding that outweigh the extra nuclear charge, so size increases and ionisation potential, electron affinity and electronegativity decrease, while metallic character increases
- Group trends: in size, in ionisation potential, in electronegativity
- Group 14 runs from non-metal to metal: carbon, silicon and germanium, tin and lead
- Metals grow more reactive down a group; non-metals grow less reactive
- Noble gases are excluded from size and electronegativity comparisons but have the highest ionisation potential in each period
- The general ionisation trend has small irregularities between some neighbours, explained in Class 11
- Chlorine's electron affinity slightly exceeds fluorine's, because fluorine's small shell repels the incoming electron
- Orders: in size, in ionisation potential, and for the mixed case
- The bottom-left corner is largest and most metallic; the top-right corner is smallest and most electronegative

The sharpest self-test is a pair of lists. Write any six elements from the first twenty, order them once by atomic size and once by ionisation potential, and check that your two orders come out as near reverses of each other — then explain every place where they do not.

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