How a Potentiometer Measures a Cell's EMF Without Drawing Any Current
Apply Kirchhoff's current and voltage laws to multi-loop circuits, use the Wheatstone bridge balance condition and the metre bridge to find unknown resistance, and use a potentiometer to compare emfs and measure internal resistance.
How do you analyse a circuit that series and parallel rules cannot simplify?
Many real circuits contain several cells and loops that no series or parallel shortcut can reduce. Two rules based on conservation of charge and energy solve all of them, and the same ideas power precise instruments for measuring resistance and emf.
This lesson covers Kirchhoff's laws, the Wheatstone and metre bridges, and the potentiometer.
This lesson covers Kirchhoff's laws, the Wheatstone and metre bridges, and the potentiometer.
How do you apply Kirchhoff's junction rule and loop rule to a circuit?
**Kirchhoff's junction rule says the currents entering a junction equal the currents leaving it, and the loop rule says the sum of emfs around any closed loop equals the sum of the potential drops, .
What each rule conserves:
- Junction rule — charge, since none piles up at a junction
- Loop rule — energy, since a charge returning to its starting point has the same potential
The method. Mark a current in every branch with a guessed direction, use the junction rule to cut the unknowns, then write one loop equation per independent loop. A negative answer simply means the real current flows the other way.
Worked example.** A 12 V cell in series with and a 6.0 V cell in series with both feed a shared resistor, with currents , and .
These simplify to and , giving
The negative shows the 12 V cell is actually charging the 6.0 V cell.
An everyday example. Jump-starting a car from another car's battery creates exactly this kind of two-cell circuit, with one battery charging the other.
The substance. Sign conventions matter more than guessed directions — crossing a resistor along the current is a drop of IR, and crossing a cell from negative to positive is a gain of .
What each rule conserves:
- Junction rule — charge, since none piles up at a junction
- Loop rule — energy, since a charge returning to its starting point has the same potential
The method. Mark a current in every branch with a guessed direction, use the junction rule to cut the unknowns, then write one loop equation per independent loop. A negative answer simply means the real current flows the other way.
Worked example.** A 12 V cell in series with and a 6.0 V cell in series with both feed a shared resistor, with currents , and .
These simplify to and , giving
The negative shows the 12 V cell is actually charging the 6.0 V cell.
An everyday example. Jump-starting a car from another car's battery creates exactly this kind of two-cell circuit, with one battery charging the other.
The substance. Sign conventions matter more than guessed directions — crossing a resistor along the current is a drop of IR, and crossing a cell from negative to positive is a gain of .
When is a Wheatstone bridge balanced, and how does a metre bridge find an unknown resistance?
**A Wheatstone bridge is balanced, with no current through the galvanometer, when , and a metre bridge uses a uniform 1 m wire as the ratio arms so that , with l in cm.
Why balance works. At balance, the two ends of the galvanometer are at the same potential, so the ratio of resistances on one side must match the other, whatever the cell's emf.
Worked example 1 — Wheatstone bridge.** With , and :
Worked example 2 — metre bridge. The unknown X sits in the left gap and a resistor in the right gap. The null point is at 40.0 cm:
Good practice:
- Choose R so the null point lies near the middle of the wire, where the percentage error is least
- Swap X and R and average the two results to cancel end errors
An everyday example. An electronic weighing scale uses strain gauges in a bridge circuit; a load unbalances the bridge, and the tiny imbalance shows up as weight.
The substance. The balance condition does not depend on the galvanometer's resistance or the cell's emf, which is why the bridge is so accurate.
Why balance works. At balance, the two ends of the galvanometer are at the same potential, so the ratio of resistances on one side must match the other, whatever the cell's emf.
Worked example 1 — Wheatstone bridge.** With , and :
Worked example 2 — metre bridge. The unknown X sits in the left gap and a resistor in the right gap. The null point is at 40.0 cm:
Good practice:
- Choose R so the null point lies near the middle of the wire, where the percentage error is least
- Swap X and R and average the two results to cancel end errors
An everyday example. An electronic weighing scale uses strain gauges in a bridge circuit; a load unbalances the bridge, and the tiny imbalance shows up as weight.
The substance. The balance condition does not depend on the galvanometer's resistance or the cell's emf, which is why the bridge is so accurate.
How does a potentiometer compare two emfs and measure a cell's internal resistance?
**A potentiometer is a long uniform wire carrying a steady current, so the potential drop along it is proportional to length; balancing a cell against a length l gives , so and .
Why it beats a voltmeter. At the balance point no current flows through the cell, so the potentiometer measures its true emf. A voltmeter always draws some current and reads the terminal voltage instead.
Worked example 1 — comparing emfs.** A driver cell sets 2.0 V across a 4.0 m wire, so V m. A 1.5 V cell balances at 3.00 m and an unknown cell at 2.20 m:
Worked example 2 — internal resistance. A cell balances at 1.20 m on open circuit. With a resistor across it, the balance moves to 1.00 m:
Conditions for a balance point:
- The driver cell's emf must exceed the emf being measured
- Positive terminals of both cells must join the same end of the wire
An everyday example. The volume knob of an old radio is a rotary potentiometer — turning it slides a contact along a resistive track to pick off a fraction of the voltage.
The substance. A longer potentiometer wire gives a smaller potential gradient, spreading the balance over more length and so improving sensitivity.
Why it beats a voltmeter. At the balance point no current flows through the cell, so the potentiometer measures its true emf. A voltmeter always draws some current and reads the terminal voltage instead.
Worked example 1 — comparing emfs.** A driver cell sets 2.0 V across a 4.0 m wire, so V m. A 1.5 V cell balances at 3.00 m and an unknown cell at 2.20 m:
Worked example 2 — internal resistance. A cell balances at 1.20 m on open circuit. With a resistor across it, the balance moves to 1.00 m:
Conditions for a balance point:
- The driver cell's emf must exceed the emf being measured
- Positive terminals of both cells must join the same end of the wire
An everyday example. The volume knob of an old radio is a rotary potentiometer — turning it slides a contact along a resistive track to pick off a fraction of the voltage.
The substance. A longer potentiometer wire gives a smaller potential gradient, spreading the balance over more length and so improving sensitivity.
Exam tip
What earns full marks on Kirchhoff's laws and bridges?
Draw the circuit with every current arrow and loop direction marked before writing equations — examiners follow the diagram to award step marks.
- Junction: ; loop:
- Wheatstone: ; metre bridge:
- Potentiometer: and
The trap. Swapping and in the internal-resistance formula. **The open-circuit length is always the longer one.**
- Junction: ; loop:
- Wheatstone: ; metre bridge:
- Potentiometer: and
The trap. Swapping and in the internal-resistance formula. **The open-circuit length is always the longer one.**
Did you know
How does a digital weighing scale turn weight into a number?
Under the platform of a digital scale sits a metal block called a load cell, with thin foil strain gauges glued to it.
When you place a bag of rice on the scale, the metal bends very slightly, stretching some gauges and squeezing others, which changes their resistance.
The gauges form a Wheatstone bridge, so this tiny change unbalances the bridge and produces a voltage that the display converts into weight.
When you place a bag of rice on the scale, the metal bends very slightly, stretching some gauges and squeezing others, which changes their resistance.
The gauges form a Wheatstone bridge, so this tiny change unbalances the bridge and produces a voltage that the display converts into weight.
Exam relevance
How do JEE Main and NEET test Kirchhoff's laws and bridge circuits?
Kirchhoff's laws and the Wheatstone bridge are core ideas in both JEE Main and NEET, reused across the whole of current electricity.
What gets asked. Branch currents in two-loop circuits, spotting a balanced bridge so the middle resistor can be ignored, metre bridge null points, and cells charging one another. Potentiometer coverage has changed in recent syllabus revisions, so check the current syllabus before spending time on it.
Question types. Mostly numericals, with symmetry-based network questions.
Why it matters later. Loop equations return in Alternating Current circuits.
The trap that costs marks. Solving a network the long way when checking first would show the bridge is balanced.
What gets asked. Branch currents in two-loop circuits, spotting a balanced bridge so the middle resistor can be ignored, metre bridge null points, and cells charging one another. Potentiometer coverage has changed in recent syllabus revisions, so check the current syllabus before spending time on it.
Question types. Mostly numericals, with symmetry-based network questions.
Why it matters later. Loop equations return in Alternating Current circuits.
The trap that costs marks. Solving a network the long way when checking first would show the bridge is balanced.
Key takeaways
What must you be able to do from this lesson?
- Kirchhoff's laws: junction rule for charge, loop rule for energy, and a negative answer means reversed current
- Bridges: at balance, and on a metre bridge
- Potentiometer: and
A metre bridge balances at 60.0 cm with in the right gap — what is the unknown resistance in the left gap?
- Bridges: at balance, and on a metre bridge
- Potentiometer: and
A metre bridge balances at 60.0 cm with in the right gap — what is the unknown resistance in the left gap?