Why Toluene Reacts Faster Than Benzene but Nitrobenzene Is Sluggish
Explain the structure and aromaticity of benzene using resonance and Huckel's rule, follow the mechanism of electrophilic aromatic substitution in nitration, halogenation and Friedel-Crafts reactions, and predict directing effects.
Why doesn't benzene behave like an ordinary alkene?
Benzene is drawn with three double bonds, yet it does not decolourise bromine water and prefers substitution to addition. Its ring of delocalised electrons gives it a special stability called aromaticity, and the groups attached to that ring decide how fast it reacts and where new groups go.
This lesson covers the structure and aromaticity of benzene, Huckel's rule, and electrophilic aromatic substitution with the directing effects of substituents.
This lesson covers the structure and aromaticity of benzene, Huckel's rule, and electrophilic aromatic substitution with the directing effects of substituents.
How does resonance explain the structure and stability of benzene?
**Benzene, , is a planar ring of six carbons whose six pi electrons are delocalised over the whole ring, so it is a resonance hybrid of two Kekule structures and is far more stable than a simple triene.
Structure:**
- Each carbon is hybridised, forming sigma bonds to two carbons and one hydrogen at 120°
- The unhybridised p orbitals on all six carbons overlap sideways above and below the ring
- The six pi electrons form a continuous ring-shaped cloud, shown by a circle inside a hexagon
Evidence for delocalisation:
- All six carbon-carbon bonds are 139 pm long, between a single bond (154 pm) and a double bond (134 pm)
- Benzene gives only one monosubstituted product, such as one bromobenzene, so all six hydrogens are equivalent
- It resists addition reactions typical of alkenes and undergoes substitution instead
Worked example — resonance energy. Hydrogenating cyclohexene, with one double bond, releases about 120 kJ mol. Three isolated double bonds would release
but hydrogenating benzene releases only about 208 kJ mol. The difference, kJ mol, is the resonance energy — the extra stability from delocalisation.
An everyday example. Washing powders use detergents built on a benzene ring, made by attaching a long alkyl chain and then a sulphonate group to benzene.
The substance. Benzene does not flip between two Kekule structures — it has one real structure in which every bond is identical.
Structure:**
- Each carbon is hybridised, forming sigma bonds to two carbons and one hydrogen at 120°
- The unhybridised p orbitals on all six carbons overlap sideways above and below the ring
- The six pi electrons form a continuous ring-shaped cloud, shown by a circle inside a hexagon
Evidence for delocalisation:
- All six carbon-carbon bonds are 139 pm long, between a single bond (154 pm) and a double bond (134 pm)
- Benzene gives only one monosubstituted product, such as one bromobenzene, so all six hydrogens are equivalent
- It resists addition reactions typical of alkenes and undergoes substitution instead
Worked example — resonance energy. Hydrogenating cyclohexene, with one double bond, releases about 120 kJ mol. Three isolated double bonds would release
but hydrogenating benzene releases only about 208 kJ mol. The difference, kJ mol, is the resonance energy — the extra stability from delocalisation.
An everyday example. Washing powders use detergents built on a benzene ring, made by attaching a long alkyl chain and then a sulphonate group to benzene.
The substance. Benzene does not flip between two Kekule structures — it has one real structure in which every bond is identical.
Formula
How do you use Huckel's rule to decide whether a compound is aromatic?
**A compound is aromatic if it is cyclic, planar and fully conjugated, with pi electrons, where n is a whole number such as 0, 1 or 2.**
All four conditions must hold:
- The molecule is cyclic
- It is planar
- Every ring atom has a p orbital, so the pi system runs unbroken around the ring
- The ring holds pi electrons
Worked examples. Solve and check for a whole number:
- Benzene — 6 pi electrons: , so aromatic
- Naphthalene — 10 pi electrons: , so aromatic
- Cyclopentadienyl anion — two double bonds plus a lone pair give 6 pi electrons, so aromatic
- Cyclopentadienyl cation — only 4 pi electrons: , so not aromatic
- Cyclooctatetraene — 8 pi electrons, , and the ring bends into a tub shape, so not aromatic
An everyday example. Naphthalene in mothballs sold at Indian general stores is aromatic, with 10 pi electrons spread over two fused rings.
The substance. A lone pair can count towards the pi electrons — in the cyclopentadienyl anion or pyridine-like rings, count only the electrons that sit in the ring's p orbitals.
All four conditions must hold:
- The molecule is cyclic
- It is planar
- Every ring atom has a p orbital, so the pi system runs unbroken around the ring
- The ring holds pi electrons
Worked examples. Solve and check for a whole number:
- Benzene — 6 pi electrons: , so aromatic
- Naphthalene — 10 pi electrons: , so aromatic
- Cyclopentadienyl anion — two double bonds plus a lone pair give 6 pi electrons, so aromatic
- Cyclopentadienyl cation — only 4 pi electrons: , so not aromatic
- Cyclooctatetraene — 8 pi electrons, , and the ring bends into a tub shape, so not aromatic
An everyday example. Naphthalene in mothballs sold at Indian general stores is aromatic, with 10 pi electrons spread over two fused rings.
The substance. A lone pair can count towards the pi electrons — in the cyclopentadienyl anion or pyridine-like rings, count only the electrons that sit in the ring's p orbitals.
How does electrophilic aromatic substitution work, and how do substituents direct it?
In electrophilic aromatic substitution, an electrophile attacks the pi electrons of benzene to form a positively charged intermediate, which loses a proton to restore the aromatic ring, and groups already on the ring decide both the speed and the position of attack.
Three-step mechanism:
- Generation of the electrophile, often with a catalyst
- Attack by the pi electrons, forming a resonance-stabilised carbocation called the arenium ion, which has temporarily lost aromaticity
- Loss of , restoring the aromatic ring
The key reactions:
- Nitration — the nitrating mixture of concentrated nitric and sulphuric acids gives the nitronium ion, , and benzene becomes nitrobenzene
- Halogenation — chlorine with anhydrous or gives , and benzene becomes chlorobenzene
- Friedel-Crafts alkylation — , giving toluene
- Friedel-Crafts acylation — with gives , and benzene becomes acetophenone
Directing effects of substituents:
- Ortho and para directing, activating — , , and push electrons into the ring, especially at the ortho and para positions
- Ortho and para directing, deactivating — the halogens withdraw electrons by the -I effect but donate lone pairs to the ortho and para positions by +R
- Meta directing, deactivating — , , , and withdraw electrons most strongly from the ortho and para positions, leaving the meta position least depleted
Worked example. Nitrating toluene gives mainly 2-nitrotoluene and 4-nitrotoluene, and it reacts faster than benzene; nitrating nitrobenzene needs harsher conditions and gives 1,3-dinitrobenzene.
An everyday example. Dye factories in Gujarat start from nitrobenzene, made by nitration, and convert it into aniline, the parent of many textile dyes.
The substance. Friedel-Crafts reactions fail on nitrobenzene — its ring is so deactivated that nitrobenzene is even used as a solvent for these reactions.
Three-step mechanism:
- Generation of the electrophile, often with a catalyst
- Attack by the pi electrons, forming a resonance-stabilised carbocation called the arenium ion, which has temporarily lost aromaticity
- Loss of , restoring the aromatic ring
The key reactions:
- Nitration — the nitrating mixture of concentrated nitric and sulphuric acids gives the nitronium ion, , and benzene becomes nitrobenzene
- Halogenation — chlorine with anhydrous or gives , and benzene becomes chlorobenzene
- Friedel-Crafts alkylation — , giving toluene
- Friedel-Crafts acylation — with gives , and benzene becomes acetophenone
Directing effects of substituents:
- Ortho and para directing, activating — , , and push electrons into the ring, especially at the ortho and para positions
- Ortho and para directing, deactivating — the halogens withdraw electrons by the -I effect but donate lone pairs to the ortho and para positions by +R
- Meta directing, deactivating — , , , and withdraw electrons most strongly from the ortho and para positions, leaving the meta position least depleted
Worked example. Nitrating toluene gives mainly 2-nitrotoluene and 4-nitrotoluene, and it reacts faster than benzene; nitrating nitrobenzene needs harsher conditions and gives 1,3-dinitrobenzene.
An everyday example. Dye factories in Gujarat start from nitrobenzene, made by nitration, and convert it into aniline, the parent of many textile dyes.
The substance. Friedel-Crafts reactions fail on nitrobenzene — its ring is so deactivated that nitrobenzene is even used as a solvent for these reactions.
Exam tip
What earns full marks on aromatic hydrocarbons?
In every substitution mechanism, show the electrophile being generated, the arenium ion and the loss of the proton — examiners mark each of the three steps.
- Aromatic: cyclic, planar, fully conjugated, pi electrons
- Nitronium ion from concentrated and ; from and
- Activating groups: ortho and para directing; halogens: ortho and para directing but deactivating
- Meta directors: , , ,
The trap. Saying benzene decolourises bromine water like an alkene. Benzene needs a Lewis acid catalyst to react with bromine, and then it substitutes rather than adds.
- Aromatic: cyclic, planar, fully conjugated, pi electrons
- Nitronium ion from concentrated and ; from and
- Activating groups: ortho and para directing; halogens: ortho and para directing but deactivating
- Meta directors: , , ,
The trap. Saying benzene decolourises bromine water like an alkene. Benzene needs a Lewis acid catalyst to react with bromine, and then it substitutes rather than adds.
Did you know
What do paracetamol, aspirin and indigo dye have in common?
Open a medicine cabinet and a wardrobe, and benzene rings are everywhere. Paracetamol and aspirin each contain a benzene ring carrying groups added by substitution reactions, and indigo, the blue dye of denim, is built from benzene rings joined to other rings.
The stability of the aromatic ring lets these molecules survive storage, cooking temperatures and washing, while the groups attached to the ring give each its particular job.
The same six-carbon ring that puzzled chemists on paper sits inside everyday tablets and clothes.
The stability of the aromatic ring lets these molecules survive storage, cooking temperatures and washing, while the groups attached to the ring give each its particular job.
The same six-carbon ring that puzzled chemists on paper sits inside everyday tablets and clothes.
Exam relevance
How do JEE Main and NEET test aromaticity and electrophilic substitution?
Hydrocarbons is a recurring chapter in both JEE Main and NEET, and aromatic chemistry is the foundation for every benzene-based compound that follows.
What gets asked. Identifying aromatic, non-aromatic and anti-aromatic species with Huckel's rule, generation of electrophiles, the steps of nitration, halogenation and Friedel-Crafts reactions, and ortho, para or meta products of substituted benzenes.
Question types. Mostly single-correct and assertion-reason questions, with JEE Advanced setting multi-step aromatic syntheses.
Why it matters later. Directing effects decide products in Haloalkanes and Haloarenes, Alcohols, Phenols and Ethers and Amines, and resonance in benzene links back to Chemical Bonding and Molecular Structure.
The trap that costs marks. Counting pi electrons wrongly in charged rings — the cyclopentadienyl anion has 6 and is aromatic, while the cation has only 4.
What gets asked. Identifying aromatic, non-aromatic and anti-aromatic species with Huckel's rule, generation of electrophiles, the steps of nitration, halogenation and Friedel-Crafts reactions, and ortho, para or meta products of substituted benzenes.
Question types. Mostly single-correct and assertion-reason questions, with JEE Advanced setting multi-step aromatic syntheses.
Why it matters later. Directing effects decide products in Haloalkanes and Haloarenes, Alcohols, Phenols and Ethers and Amines, and resonance in benzene links back to Chemical Bonding and Molecular Structure.
The trap that costs marks. Counting pi electrons wrongly in charged rings — the cyclopentadienyl anion has 6 and is aromatic, while the cation has only 4.
Key takeaways
What must you be able to do from this lesson?
- Benzene: a planar ring of carbons with delocalised pi electrons, equal bond lengths and a resonance energy of about 152 kJ mol
- Huckel's rule: cyclic, planar, fully conjugated rings with pi electrons are aromatic
- Electrophilic substitution: nitration, halogenation and Friedel-Crafts reactions, with activating, deactivating, ortho, para and meta directing groups
What is the main product when nitrobenzene is nitrated again, and why does the second nitro group go where it does?
- Huckel's rule: cyclic, planar, fully conjugated rings with pi electrons are aromatic
- Electrophilic substitution: nitration, halogenation and Friedel-Crafts reactions, with activating, deactivating, ortho, para and meta directing groups
What is the main product when nitrobenzene is nitrated again, and why does the second nitro group go where it does?