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Why Large Telescopes Use Curved Mirrors Instead of Lenses

Derive the relation between refractive index, prism angle and minimum deviation and explain dispersion, derive the magnifying power of simple and compound microscopes, and compare refracting and reflecting telescopes.

How do prisms, microscopes and telescopes all bend light to reveal what the eye cannot see?

A glass prism splits white light into colours, a microscope shows the cells in a drop of blood, and a telescope brings the craters of the Moon into view. Each works by refracting or reflecting light in a way that a few derivations make precise.

This lesson covers minimum deviation and dispersion, simple and compound microscopes, and refracting and reflecting telescopes.

How do you derive the refractive index of a prism from the angle of minimum deviation, and what causes dispersion?

**At minimum deviation the ray passes symmetrically through the prism, giving , and dispersion happens because n is larger for violet light than for red.

The derivation.** For any ray, and the deviation is . At minimum deviation, and , so . Snell's law then gives the formula.

Worked example 1. A prism of angle gives :



Thin prisms and dispersion. For a small angle A, . Since , violet deviates more, and the dispersive power is .

Worked example 2. A thin prism has , and mean :



An everyday example. The glass pieces of a chandelier throw small patches of rainbow colours onto the walls, each acting as a prism.

The substance. At minimum deviation, a slightly larger or smaller angle of incidence both increase the deviation — which is why the minimum can be found reliably by rotating the prism.

How do you derive the magnifying power of a simple and a compound microscope?

**A simple microscope has magnifying power with the image at the near point, where cm, and a compound microscope has .

Simple microscope.** Magnifying power is the ratio of the angle the image subtends to the angle the object subtends at the near point. With the image at , the lens formula gives the object distance, and . With the image at infinity, .

Worked example 1. A lens of cm gives at the near point and at infinity.

Compound microscope. The objective forms a real, magnified image, which the eyepiece then magnifies like a simple microscope.

Worked example 2. An objective of cm, an object at cm, and an eyepiece of cm:





The final image is 30 times larger in angle, and inverted.

An everyday example. A pathology lab technician uses a compound microscope to count blood cells that no simple lens could separate.

The substance. Both lenses of a compound microscope should have short focal lengths, with the objective's even shorter, since M grows as and shrink.

How do you find the magnifying power of refracting and reflecting telescopes, and which is better?

**In normal adjustment a telescope has magnifying power and length , whether its objective is a lens or a concave mirror; reflecting telescopes avoid chromatic aberration and can be built far larger.

Refracting telescope.** A long-focus objective lens forms a real image of a distant object at its focus, and a short-focus eyepiece magnifies it. With the final image at the near point, .

Worked example 1. cm and cm:



Reflecting telescope. A concave mirror of focal length collects the light, and a small secondary mirror sends it to the eyepiece.

Worked example 2. A mirror of radius 4.0 m, so m, with a 2.5 cm eyepiece gives .

Comparing the two:

- Reflectors — no chromatic aberration; a parabolic mirror removes spherical aberration; a mirror can be supported from behind, so it can be made very large
- Refractors — no secondary mirror blocking part of the light, but large lenses sag under their weight and suffer chromatic aberration

An everyday example. At a planetarium's sky-watching evening, the telescopes that show Saturn's rings are often reflectors.

The substance. A larger objective does not raise magnification — it gathers more light and resolves finer detail, while magnification depends on the focal-length ratio.
Exam tip

What earns full marks on prisms and optical instruments?

Draw a labelled ray diagram for every instrument derivation, showing where the intermediate image forms — examiners award separate marks for the diagram.

- Prism: ; thin prism
- Simple microscope: or
- Compound microscope:
- Telescope: , length

The trap. Using the near-point formula when the question says normal adjustment. Normal adjustment means the final image is at infinity.
Did you know

Why do telescopes in space see more sharply than telescopes on the ground?

Air is never perfectly still. Pockets of warmer and cooler air have slightly different refractive indices, and as they drift across a telescope's view they bend starlight this way and that.

This blurs images and is the same effect that makes stars appear to twinkle.

A telescope placed above the atmosphere escapes the problem entirely, so even a modest mirror in space can often match the sharpness of a larger one on the ground.
Exam relevance

How do JEE Main and NEET test prisms and optical instruments?

Prisms and optical instruments are recurring parts of the Ray Optics chapter in both JEE Main and NEET.

What gets asked. Minimum deviation and refractive index, thin-prism deviation and dispersion, magnifying power and tube length of microscopes and telescopes, and which lens to use as objective or eyepiece.

Question types. Mostly numericals, with graph questions on deviation against angle of incidence.

Why it matters later. Resolving power of microscopes and telescopes returns in Wave Optics through diffraction.

The trap that costs marks. Mixing up which focal length should be larger — a telescope needs a long-focus objective, but a microscope needs a short-focus one.
Key takeaways

What must you be able to do from this lesson?

- Prisms: derive from and , and explain dispersion with
- Microscopes: for a simple one and for a compound one
- Telescopes: in normal adjustment, and why reflectors beat refractors at large sizes

A telescope in normal adjustment is 44 cm long with a magnifying power of 10 — can you find both focal lengths?

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